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Message Posted: Tue, 22 Jun 2004 @ 16:03:12 GMT

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Hi Micheal,

I tried with your work-around method it didnt solve my problem because my result is of 18 decimal precision and even if I add/sub .000000000000000001 in numerator/denominator it still gives me the same result. Even if it works out also my case is different I need to make 19th decimal to be < 5 and if do something .0000000000000000001 TD gives me Numeric Overflow result.

Thanks & Regards,

Prasanna Kambhoji

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